解答例1 †
#include <stdio.h>
int main(void){
int x = 30, y = 4;
double z = (double) x / y;
printf("%f\n", z);
return 0;
}
解答例2 †
#include <stdio.h>
int main(void){
int x = 30, y = 4;
double z = x /(double) y;
printf("%f\n", z);
return 0;
}
解答例3 †
#include <stdio.h>
int main(void){
int x = 30, y = 4;
double z = (double) x /(double) y;
printf("%f\n", z);
return 0;
}
解答例4 †
#include <stdio.h>
int main(void){
printf("%f\n", (double) 30 / 4);
return 0;
}
解答例5 †
#include <stdio.h>
int main(void){
printf("%f\n", 30 / (double) 4);
return 0;
}
解答例6 †
#include <stdio.h>
int main(void){
printf("%f\n", (double) 30 / (double) 4);
return 0;
}