02B-2

解答例1 †

#include <stdio.h>

int main(void){
  double x = 3.5, y = 2.5;
  double z = x - y;
  printf("%f\n", z);
  return 0;
}

解答例2 †

#include <stdio.h>

int main(void){
  printf("%f\n", 3.5 - 2.5);
  return 0;
}